Asked by Kirk
ok so having trouble with this have tried and trie but can seeem to come up with tthe answer. d/(1-d)^2=(d+1)^2 - 1/d
the answer we were given is d^5-2d^3-2d^2+3d-1=0
the answer we were given is d^5-2d^3-2d^2+3d-1=0
Answers
Answered by
Reiny
d/(1-d)^2=(d+1)^2 - 1/d
the LCD = d(1-d)^2
so multiply each term by that
d^2 = d(1-d)^2 (d+1)^2 - (1-d)^2
d^2 + (1-d)^2 = d[(1-d)(1+d)]^2
d^2 + (1-d)^2 = d[(1-d^2]^2
d^2 + 1 - 2d + d^2 = d(1 - 2d^2 + d^4)
d^2 + 1 - 2d + d^2 = d - 2d^3 + d^5
d^5 - 2d^3 - 2d^2 + 3d - 1 = 0 as shown in your answer
the LCD = d(1-d)^2
so multiply each term by that
d^2 = d(1-d)^2 (d+1)^2 - (1-d)^2
d^2 + (1-d)^2 = d[(1-d)(1+d)]^2
d^2 + (1-d)^2 = d[(1-d^2]^2
d^2 + 1 - 2d + d^2 = d(1 - 2d^2 + d^4)
d^2 + 1 - 2d + d^2 = d - 2d^3 + d^5
d^5 - 2d^3 - 2d^2 + 3d - 1 = 0 as shown in your answer
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.