Asked by Alex
I have been stuck on this for a while now and cant figure out what it is i am doing wrong HELP!!!
A tennis ball with a velocity of 15.5 m/s is
thrown perpendicularly at a wall. After strik-
ing the wall, the ball rebounds in the opposite
direction with a speed of 9.3 m/s.
If the ball is in contact with the wall for
0.015 s, what is the average acceleration of
the ball while it is in contact with the wall?
A tennis ball with a velocity of 15.5 m/s is
thrown perpendicularly at a wall. After strik-
ing the wall, the ball rebounds in the opposite
direction with a speed of 9.3 m/s.
If the ball is in contact with the wall for
0.015 s, what is the average acceleration of
the ball while it is in contact with the wall?
Answers
Answered by
Henry
aq = (V-Vo)/t = (-9.3-15.5) 0.015=-1660
m/s^2.
NOTE: The final velocity is in the opposite direction. Therefore, it is
NEGATIVE.
A 2nd interpretation:
While the ball is in contact with the wall, its' velocity is o.
a = (0-15.5) / 0.015 = 1033.3 m/s^2.
m/s^2.
NOTE: The final velocity is in the opposite direction. Therefore, it is
NEGATIVE.
A 2nd interpretation:
While the ball is in contact with the wall, its' velocity is o.
a = (0-15.5) / 0.015 = 1033.3 m/s^2.
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