Asked by Losa
A buffet-style restaurant has 18 tables that seat 23 people each. A church group of 401 has rented the restaurant for a banquet. If the pastor of another church, his wife, and their nine children come as invited guests, what is the least number of people can sit at any one table?- Please help Ms.Sue and Writeacher.
Answers
Answered by
Ms. Sue
401 + 11 = 412
412 / 18 = 22.9
412 / 18 = 22.9
Answered by
i know better than that
Oh Ms.Sue! That almost look like the story problem that was an example in the previous page in my math book! I should follow that. Thank you very much Ms.Sue!
Answered by
Losa
Sorry for that Ms.Sue. But seriously thank you!
Answered by
Ms. Sue
You're very welcome. Losa. :-)
Answered by
Ms. Sue
What is your answer?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.