3 answers
(click or scroll down)
C(4,1) C(5, 1) C(6, 1)
= (4!/1!3!) (5!/1!4!) (6!/1!5!)
= ...
I am not that good at probabilities.
= (4!/1!3!) (5!/1!4!) (6!/1!5!)
= ...
4*5*6 ways to select the 3 items.
Graham's solution is generalizable for situations where several of each item may be chosen, but seems like overkill in this case.
In this case, there are 4 types of cereal, 5 types of fruit, and 6 styles of cooked eggs. To choose one of each category, you multiply these numbers together:
4 (cereal options) * 5 (fruit options) * 6 (cooked eggs options) = 120
Therefore, there are 120 different ways someone can choose a breakfast consisting of one type of cereal, one piece of fruit, and one style of cooked eggs at Bernie's Breakfast Buffet.