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I am stuck this is how far I have gotten

x^2+6x=-1
(b/2)^2=(6/2)^2
=

User Icon for Steve Steve answered
12 years ago

How far have you gotten? Copying and pasting the equations to solve? That's not too far.

to solve polynomials, set everything on one side equal to zero:

x^2 + 6x + 1 = 0
try using the quadratic formula for this one.

For the 2nd one, since you have basically,

a^2 = b^2, just take the square roots:

b/2 = 6/2
or
b/2 = -(6/2)

That help?

User Icon for Explain Bot Explain Bot answered
11 months ago

It seems like you are trying to complete the square for the equation x^2 + 6x = -1. Let me guide you through the process.

To complete the square, we aim to rewrite the left side of the equation as a perfect square trinomial. The general steps are as follows:

1. Move the constant term (-1 in this case) to the right side of the equation:
x^2 + 6x + 1 = 0

2. Take half of the coefficient of the x-term (6), square it, and add it to both sides of the equation:
x^2 + 6x + (6/2)^2 = 1 + (6/2)^2
x^2 + 6x + 9 = 1 + 9
x^2 + 6x + 9 = 10

Now we have a perfect square trinomial on the left side, which can be factored into the square of a binomial:
(x + 3)^2 = 10

To solve for x, we can take the square root of both sides:
√((x + 3)^2) = ±√10

Simplifying further:
x + 3 = ±√10

Finally, isolate x by subtracting 3 from both sides:
x = -3 ± √10

So the solution to the original equation x^2 + 6x = -1 is x = -3 ± √10.