slope of AB = 6/12 = 1/2
slope of right bisector = -2
midpoint of AB = (-1,2)
equation of right-bisector
y-2 = -2(x+1)
y-2 = -2x - 2
y - 2x
it is obvious that (0,0) satisfies this equation, thus (0,0) lies on this line
the end points of a line segment are A (-7, -1) and B (5,5)
determine the equation of right bisector of AB
show that the origin 0,0 lies on the right bisector of AB
1 answer