Asked by Pat
Are these right?!
Absolute value :
1. |x^2-2x+16|=8
x=-4
x=-3
x=-2
x=2
2.|3x-2|=7
x=5\3
x=3
3. |3x+2|+3=0
x= -5/3
Absolute value :
1. |x^2-2x+16|=8
x=-4
x=-3
x=-2
x=2
2.|3x-2|=7
x=5\3
x=3
3. |3x+2|+3=0
x= -5/3
Answers
Answered by
Reiny
1.
x^2 - 2x + 16 = 8 or x^2 - 2x + 16 = -8
x^2 - 2x + 8 = 0 or x^2 - 2x + 24 = 0
neither the first nor the second has a real solution.
2. |3x-2| = 7
3x-2=7 or 3x-2=-7
3x=9 or 3x = -5
x = 3 or x = -5/3
3.
|3x+2| = -3
by its very definition, there cannot be a solution here.
x^2 - 2x + 16 = 8 or x^2 - 2x + 16 = -8
x^2 - 2x + 8 = 0 or x^2 - 2x + 24 = 0
neither the first nor the second has a real solution.
2. |3x-2| = 7
3x-2=7 or 3x-2=-7
3x=9 or 3x = -5
x = 3 or x = -5/3
3.
|3x+2| = -3
by its very definition, there cannot be a solution here.
Answered by
Unknown.
In the first problem it was suppose to be -16
my mistake, but does it still g=have no solution?
my mistake, but does it still g=have no solution?
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