Asked by Chris
                Making Sure these are right?
absolute value:
1.|7x+2|=10
x=1.1 x=1.7
2.|3x-5|=-1
x=1.3 x=2
            
        absolute value:
1.|7x+2|=10
x=1.1 x=1.7
2.|3x-5|=-1
x=1.3 x=2
Answers
                    Answered by
            Bosnian
            
    1. Eliminate the absoulute value :
7 x + 2 = 10
7 x + 2 = - 10
_________________
7 x + 2 = 10
7 x = 10 - 2 = 8
x = 8 / 7
7 x + 2 = - 10
7 x = - 10 - 2 = - 12
x = - 12 / 7
Solutions x = 8 / 7 aprox. 1.14 and x = - 12 / 7 aprox. - 1.71
2.Eliminate the absoulute value :
Absolute value can't be negative.
No solutions exist.
    
7 x + 2 = 10
7 x + 2 = - 10
_________________
7 x + 2 = 10
7 x = 10 - 2 = 8
x = 8 / 7
7 x + 2 = - 10
7 x = - 10 - 2 = - 12
x = - 12 / 7
Solutions x = 8 / 7 aprox. 1.14 and x = - 12 / 7 aprox. - 1.71
2.Eliminate the absoulute value :
Absolute value can't be negative.
No solutions exist.
                    Answered by
            Chris
            
    So if the absolute vale equals a negative number there is no solution?
Such as:
|x^2+2x+1|=-4
So, that has no solution?
    
Such as:
|x^2+2x+1|=-4
So, that has no solution?
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