Asked by Albert
Please let me know if I answered these correctly. thank you,
#2. Add:
3p^2 – 5p – 4 and 9p^2 + 10p – 2
A. 12p2 + 15p – 6
B. 12p2 + 5p – 2
C. 12p2 + 5p – 6
D. 12p2 + 15p – 2
answer D
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#7.
(3x^2 – 2x – 1)(x^2 + x + 5)
A. 3x^4 + 2x^3 + 12x^2 – 11x – 5
B. 3x^4 + x^3 + 12x^2 – 10x – 5
C. 3x^4 + x^3 + 12x^2 – 11x – 5
D. 3x^4 + x^3 + 14x^2 – 11x – 5
Answer is B
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#9.
Factor completely relative to the integers.
x^2 – 8x + x – 8
A. (x + 8)(x – 1)
B. (x – 8)(x – 1)
C. (x + 1)(x + 8)
D. (x – 8)(x + 1)
Answer D.
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#10. Factor completely relative to the integers.
25x^2 – 5x – 2
A. (5x – 2)(5x + 1)
B. (5x + 2)(5x – 1)
C. (25x – 2)(x + 1)
D. (5x + 1)(5x – 2)
Answer B.
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#2. Add:
3p^2 – 5p – 4 and 9p^2 + 10p – 2
A. 12p2 + 15p – 6
B. 12p2 + 5p – 2
C. 12p2 + 5p – 6
D. 12p2 + 15p – 2
answer D
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#7.
(3x^2 – 2x – 1)(x^2 + x + 5)
A. 3x^4 + 2x^3 + 12x^2 – 11x – 5
B. 3x^4 + x^3 + 12x^2 – 10x – 5
C. 3x^4 + x^3 + 12x^2 – 11x – 5
D. 3x^4 + x^3 + 14x^2 – 11x – 5
Answer is B
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#9.
Factor completely relative to the integers.
x^2 – 8x + x – 8
A. (x + 8)(x – 1)
B. (x – 8)(x – 1)
C. (x + 1)(x + 8)
D. (x – 8)(x + 1)
Answer D.
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#10. Factor completely relative to the integers.
25x^2 – 5x – 2
A. (5x – 2)(5x + 1)
B. (5x + 2)(5x – 1)
C. (25x – 2)(x + 1)
D. (5x + 1)(5x – 2)
Answer B.
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Answers
Answered by
Steve
#2. No. (C):
-5p+10p = +5p, not +15p
-4 -2 = -6
#7. No. (C):
-2x(5) - 1(x) = -11x
#9. Yes!
#10. No. (D)
you want -10x, and +1(5x) + 5x(-2) = -10x
-5p+10p = +5p, not +15p
-4 -2 = -6
#7. No. (C):
-2x(5) - 1(x) = -11x
#9. Yes!
#10. No. (D)
you want -10x, and +1(5x) + 5x(-2) = -10x
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