Asked by Cindy
I have a project practical investigation to do and I have no idea how to go about with it. The problem is: Calculate the mass of sodium hydroxide used to prepare a 0,5M NaOH solution in a 250ml volumetric flask. Determine the concentration of the acetic acid solution used (vinegar).
Answers
Answered by
Steve
ummm, why would you use acetic acid to prepare a NaOH solution?
Anyway, 250mL of .5M NaOH contains .125 moles NaOH = .125(23+16+1) = 5 grams
Anyway, 250mL of .5M NaOH contains .125 moles NaOH = .125(23+16+1) = 5 grams
Answered by
joe
.25L times .5M=.125moles
.125 times 40= 5 grams
.125 times 40= 5 grams
Answered by
Kyle
They did the right work but the answer is 40 grams. That is what it says in the book.
There are no AI answers yet. The ability to request AI answers is coming soon!