Asked by Anzi
What is the limit of cosx/log(x-phi/2+1) if lim x is to phi/2
Answers
Answered by
Steve
we have 0/0, so try
-sinx / (1/(x-pi/2+1))
= -1 / (1/1)
= -1
-sinx / (1/(x-pi/2+1))
= -1 / (1/1)
= -1
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