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Original Question
Find the remainder when 1!+2!+...+299!+300! is divided by 21

Asked by john

Find the remainder when 1!+2!+...+299!+300! is divided by 21
13 years ago

Answers

Answered by MathMate
If you note that we only need to calculate

6
s=∑ i!
n=1

or

s=873 mod 21 = 12

Because all terms 7! and beyond are divisible by 21.
13 years ago

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