Asked by Greg
A buffer is prepared by transferring equal concentrations of the components of the conjugate pair, C6H5COOH and C6H5COONa, into a beaker. What is the approximate pH of the buffer? (Ka = 6.5 10–5)
a) 2.81
b) 4.19
c) 7.00
d) 9.81
e) 11.19
a) 2.81
b) 4.19
c) 7.00
d) 9.81
e) 11.19
Answers
Answered by
DrBob222
pH = pKa BECAUSE
pH = pKa + log (base)/(acid)
base = acid; therefore,
base/acied = 1 and
pH = pKa + log 1
pH = pKa + 0
pH = pKa.
pH = pKa + log (base)/(acid)
base = acid; therefore,
base/acied = 1 and
pH = pKa + log 1
pH = pKa + 0
pH = pKa.
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