Question

An automobile starts from rest and 110
ft attains a speed of 30 mi/h. In what time has it traveled this distance and the is the acceleration?

Answer 1

v=at
=>a=v/t,
s=a•t²/2=v•t²/2•t=v•t/2.
t=2•s/v.

Answer 2

i don't kwon

Answer 3

convert first the given:
30mph=13.415m/s
110ft=33.521m
a=?
V(final)^2=V(initial)^2+2as
substitute:
(13.415)^2=(0)^2+2a(33.521)
179.962=220a
a=5.37m/s/s
t=?
S=V(initial)t+1/2at^2
substitue to find the value of t:
33.521=1/2(5.37)t^2
t^2=12.485
t=3.5sec

Answer 4

convert first the given:
30mph=13.408m/s
110ft=33.521m
a=?
V(final)^2=V(initial) ^2+2as
substitute:
(13.408m/s)^2=(0m/s)^2+2(a)(33.521m)
179.774=67.042a
a=2.682m/

t=?
S=V(initial)(t)+1/2(a)(t)^2
substitute:
33.521=0(t)+1/2(2.682)(t)^2
33.521=1.341t^2
t^2=24.997
t=4.9997sec~5sec

Answer 5

convert first the given:
30mph=13.408m/s
110ft=33.521m
a=?
V(final)^2=V(initial) ^2+2as
substitute:
(13.408m/s)^2=(0m/s)^2+2(a)(33.521m)
179.774=67.042a
a=2.682m/s^2


t=?
S=V(initial)(t)+1/2(a)(t)^2
substitute:
33.521=0(t)+1/2(2.682)(t)^2
33.521=1.341t^2
t^2=24.997
t=4.9997sec or 5sec