Asked by Anonymous

A grinding wheel of radius 0.280 m rotating on a frictionless axle is brought to rest by applying a constant friction force tangential to its rim. The constant torque produced by this force is 75.3 N · m. Find the magnitude of the friction force.
Answered by drwls
(friction force) * (radius) = torque

Solve for the friction force, in Newtons.

75.3/0.28 = ___ N
Answered by jackie mvsu
Torque=r x friction
so...solve for friction for

torque is known:75.3 Nm
radius is known:0.280m

so Torque/radius=75.3Nm/0.280m
meters cancel out =269N
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