Question
At t=0 a grinding wheel has an angular velocity of 24.0rad/s . It has a constant angular acceleration of 35.0rad/s2 until a circuit breaker trips at time t = 1.90s . From then on, it turns through an angle 436rad as it coasts to a stop at constant angular acceleration.
Through what total angle did the wheel turn between t=0 and the time it stopped?
At what time did it stop?
What was its acceleration as it slowed down?
Through what total angle did the wheel turn between t=0 and the time it stopped?
At what time did it stop?
What was its acceleration as it slowed down?
Answers
Damon
v = Vi + a t
Vend = 24 + 35 (1.9)
angle at 1.9 s = 1.9(Vi+Vend)/2
total angle = 436 + angle at 1.9 s
time at Vend = 1.9 + 436/Vend
Vend = 24 + 35 (1.9)
angle at 1.9 s = 1.9(Vi+Vend)/2
total angle = 436 + angle at 1.9 s
time at Vend = 1.9 + 436/Vend