Asked by velma
A 1.50 kg mass attached to a spring oscillates with a period of 0.365 s and an amplitude of 15.5 cm.
(a) Find the total mechanical energy of the system
(a) Find the total mechanical energy of the system
Answers
Answered by
ajayb
T = 2*pi*sqrt(m/k)
so k = 4*pi^2*m/T^2 = 444.5 N/m
E = (1/2)*k*A^2 = (1/2)*444.5*0.155^2
= 5.34 J
so k = 4*pi^2*m/T^2 = 444.5 N/m
E = (1/2)*k*A^2 = (1/2)*444.5*0.155^2
= 5.34 J
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