Asked by sanjay
A mass of 100 gm is attached to the end of a rubber string 49 cm long n hving sn area of cross section 20 sqmm. The string is whirled around, horizontally at a cnstnt speed of 40 rps in a crcl of radius 51 cm. Find the young's modulus of rubber.
Answers
Answered by
bobpursley
find the force/area.
Force from centripetal force by
force=v^2/r (change rps to m/s)
then, you know the elongation, and the crosssectional area.
then solve for Young's modulus..
https://ccrma.stanford.edu/~jos/pasp/Young_s_Modulus_Spring_Constant.html
Force from centripetal force by
force=v^2/r (change rps to m/s)
then, you know the elongation, and the crosssectional area.
then solve for Young's modulus..
https://ccrma.stanford.edu/~jos/pasp/Young_s_Modulus_Spring_Constant.html
Answered by
Diya
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