Question
Cesium-137 has a half life of 30.0 years. If initially there are 8.0 kg of cesium-137 present in a sample, how many kg will remain after 60.0 years?
Answers
k = 0.693/t<sub>1/2</sub> and substitute k into the equation below.
ln(No/N) = kt
No = 8 kg
N = ?
k from above
t = 60.0 years.
ln(No/N) = kt
No = 8 kg
N = ?
k from above
t = 60.0 years.
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