Asked by brian
Cesium-137 has a half life of 30.0 years. If initially there are 8.0 kg of cesium-137 present in a sample, how many kg will remain after 60.0 years?
Answers
Answered by
DrBob222
k = 0.693/t<sub>1/2</sub> and substitute k into the equation below.
ln(No/N) = kt
No = 8 kg
N = ?
k from above
t = 60.0 years.
ln(No/N) = kt
No = 8 kg
N = ?
k from above
t = 60.0 years.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.