Asked by Tristan
Consider that the half-life of Polonium-210 is 140 days.What approximate daily percentage of decay does Polonium-210 demonstrate?% (Round to two decimals.)(Hint: use the Rule of 70 backwards by dividing by the half-life period instead of the rate.) What percentage of the original amount of Polonium-210 would be left after 425 days of decay? % (Round to two decimals.)
Answers
Answered by
Steve
the fraction left after d days is
0.5^(d/140)
So, after 1 day, that is 0.99506 for a daily decay rate of 0.494%
Now just plug in d=425
0.5^(d/140)
So, after 1 day, that is 0.99506 for a daily decay rate of 0.494%
Now just plug in d=425
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.