Asked by Big Trav

Silver tarnishes (turns to Ag2S) in the presence of oxygen and hydrogen sulfide according to the following equation:

4Ag(s) + 2H2S(g) + O2(g) ¨ 2Ag2S(s) + 2H2O(l)

Usually, H2S is the limiting reactant. If a silver spoon is placed in a container that holds 56.7mL of H2S at 1.23atm and 22‹C, how many grams of silver on the spoon will tarnish
Answered by DrBob222
Use PV = nRT and solve for n = number of mols H2S at the conditions listed. Then convert mols H2S to mols Ag using the coefficients in the balanced equation. Finally, g Ag = mols Ag x atomic mass Ag.
Answered by Anonymous
16.172 grams
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