Question
The solubility of Ag2S is 2.48x10^-15 mol/dm3. Calculate its solubility product.
Answers
bobpursley
Write the equation:
Ag2S<<>>2Ag+ + S-- when in equilibrium
ksp= [Ag+]^2 [S--]/[Ag2S]
ksp= (2x)^2 (x)/x
you are given x as 2.48E-15
solve for ksp
=4x^2
Ag2S<<>>2Ag+ + S-- when in equilibrium
ksp= [Ag+]^2 [S--]/[Ag2S]
ksp= (2x)^2 (x)/x
you are given x as 2.48E-15
solve for ksp
=4x^2