Asked by andy
Compute the derivative for the following:
n(x) = sin(x^3-5x^2+4x-7)
Thanks,
andy
n(x) = sin(x^3-5x^2+4x-7)
Thanks,
andy
Answers
Answered by
bobpursley
n' = cos(x^3-5x^2+4x-7) * (3x^2-10x+4)
Answered by
Bosnian
Go on: wolframalpha dot com
When page be open in rectangle type:
derivative sin(x^3-5x^2+4x-7)
and click option =
After few seconds when you see result click option:
Show steps
On wolfram alpha dot com you can practice any kind of calculus.
That is good just for practice.
You can't use wolfram alpha on exam.
When page be open in rectangle type:
derivative sin(x^3-5x^2+4x-7)
and click option =
After few seconds when you see result click option:
Show steps
On wolfram alpha dot com you can practice any kind of calculus.
That is good just for practice.
You can't use wolfram alpha on exam.
Answered by
andy
Thanks Much!
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