Asked by robyn
Assume that a sample is used to estimate a population proportion p. Find the margin of error M.E. that corresponds to a sample of size 344 with 96 successes at a confidence level of 98%.
Answers
Answered by
MathGuru
Margin of error = (2.33)[√(pq/n)]
...where p = 96/344, q = 1 - p, and n = 344
Note: 2.33 represents 98% confidence interval.
Convert all fractions to decimals.
Plug the values into the formula and calculate.
I let you take it from here.
...where p = 96/344, q = 1 - p, and n = 344
Note: 2.33 represents 98% confidence interval.
Convert all fractions to decimals.
Plug the values into the formula and calculate.
I let you take it from here.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.