Question
repost sorry about that
(k^1/8)^-4 oer(k^7)^1/2
(k^1/8)^-4 oer(k^7)^1/2
Answers
Reiny
(k^1/8)^-4 over (k^7)^1/2
= k^(-1/2) / k^(7/2)
= k^-4 or 1/k^4
= k^(-1/2) / k^(7/2)
= k^-4 or 1/k^4