I'm not 100% sure but try this.
Heat(vap) = Delta H (gas) - Delta H (liquid).
Doing that I got 42kj/mol.
The normal boiling point of ethanol is 78.5C. Using the following information:
delta H formation (C2H5OH (g))= -234.38 kJ/mol determine the enthalpy of vaporization of ethanol.
I know it should be around 39.3 according to a table in my textbook, however, I don't know how to get this answer using the information given. Please help show me the steps so I can learn how to do this! thank you!!!!
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