The normal boiling point of Rh is 3727°C. What is its vapor pressure in mm Hg at 2914°C, if its heat of vaporization is 557.0 kJ/mol?

Answer 1

Use the Clausius-Clapeyron equation

Answer 2

I don't understand that equation. Which part of what's given would fit into it? T1=3727 T2=2914 then convert to kelvin. delta h is 557.0. but what do i use for R..or is that what i am looking for?

Answer 3

oh R is constant.

Answer 4

Yes, R is 8.314
Then P1 goes with T1 and P2 goes with T2.
Delta H is 557.0 kJ/mol but you should use 557,000 in the formula;i.e., convert to J/mol.