Question

A force of 13 N is needed to keep a spring with a 2-kg mass stretched 0.25 m beyond its natural length. The damping constant of the spring is c = 8. If the mass starts at the equilibrium position with a velocity of 0.5 m/s, find its position at time t.

Answer 1

Position at time t = 0.25 m + 0.5 m/s * t - (13 N / (2 kg * 8)) * e^(-8t)