Question
A force of 10N is needed to move a mass of 2kg resting on a table. Find the coefficient of friction. ( take g=9.8m/s)
Answers
Damon
weight = m g = 2*9.8 = 19.6 N
mu * 19.6 = 10
mu = o,.51
mu * 19.6 = 10
mu = o,.51
david agom
Demon are you saying this is my correct answer? Wats the meaning of mu?
Damon
hummm
mu is my English typing of the Greek letter for coef of friction
coef of friction = .51
mu is my English typing of the Greek letter for coef of friction
coef of friction = .51
david agom
That's very interesting. Thanks any were. Ama like to get your cell number
Damon
LOL, if I had one :)
(but not allowed anyway)
(but not allowed anyway)
david agom
How long did it take you before you knew how to do all this solvings?
Damon
Started high school in 1951
david agom
07039296179 okey flash me I want us to talk strickly on academic matters!!!! Pls
Damon
I can not do that. I can only respond here.
david agom
In my last question, how did you get 0.51 as your last answer coz force of wasn't multiplied, either was it divided! Were did the 0.51 come from?
Damon
mu * weight = friction force
mu = friction force / weight
= 10/19.6
= .51
mu = friction force / weight
= 10/19.6
= .51
Damon
You are given that 10 Newtons is the friction force you have to overcome.
david agom
That's good, but if I fail this calculations by tomao eehhh hmm I go find you!!!!!! How can I get the web adress to this site? You know I searched through Google..... I wanna get the website adress!
Damon
http://www.jiskha.com/
david agom
In my last question, how did you get 0.51 as your last answer coz force of wasn't multiplied, either was it divided! Were did the 0.51 come from?