Asked by david agom

A force of 10N is needed to move a mass of 2kg resting on a table. Find the coefficient of friction. ( take g=9.8m/s)
Answered by Damon
weight = m g = 2*9.8 = 19.6 N

mu * 19.6 = 10

mu = o,.51
Answered by david agom
Demon are you saying this is my correct answer? Wats the meaning of mu?
Answered by Damon
hummm

mu is my English typing of the Greek letter for coef of friction

coef of friction = .51

Answered by david agom
That's very interesting. Thanks any were. Ama like to get your cell number
Answered by Damon
LOL, if I had one :)
(but not allowed anyway)
Answered by david agom
How long did it take you before you knew how to do all this solvings?
Answered by Damon
Started high school in 1951
Answered by david agom
07039296179 okey flash me I want us to talk strickly on academic matters!!!! Pls
Answered by Damon
I can not do that. I can only respond here.
Answered by david agom
In my last question, how did you get 0.51 as your last answer coz force of wasn't multiplied, either was it divided! Were did the 0.51 come from?
Answered by Damon
mu * weight = friction force
mu = friction force / weight

= 10/19.6

= .51
Answered by Damon
You are given that 10 Newtons is the friction force you have to overcome.
Answered by david agom
That's good, but if I fail this calculations by tomao eehhh hmm I go find you!!!!!! How can I get the web adress to this site? You know I searched through Google..... I wanna get the website adress!
Answered by Damon
http://www.jiskha.com/
Answered by david agom
In my last question, how did you get 0.51 as your last answer coz force of wasn't multiplied, either was it divided! Were did the 0.51 come from?
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