Asked by Hale
How much force is needed to bring a 3200 lb car from rest to a velocity of 44 ft/s in 8 seconds? Please indicate the formula used.
Answers
Answered by
drwls
Please keep the same name for your posts. This will be the last of your questions that I answer.
The formula to use is
F = M * a
M must be in slugs (and equals 99.4 slugs) and the acceleration is
a = (44 ft/s)/8 s = 5.5 ft/s^2.
The force F that you compute,
99.4 slugs * 5.4 ft/s^2, will be in pounds.
Note that 1 lb force = 1 slug*ft/s^2
Although 1 pound of mass has a weight force of 1 pound on Earth, it is essential that Weight and mass have different units when doing physics and engineering problems, because force and mass are NOT the same thing.
The formula to use is
F = M * a
M must be in slugs (and equals 99.4 slugs) and the acceleration is
a = (44 ft/s)/8 s = 5.5 ft/s^2.
The force F that you compute,
99.4 slugs * 5.4 ft/s^2, will be in pounds.
Note that 1 lb force = 1 slug*ft/s^2
Although 1 pound of mass has a weight force of 1 pound on Earth, it is essential that Weight and mass have different units when doing physics and engineering problems, because force and mass are NOT the same thing.
Answered by
Maria Ellah
Ok sir! TNX!
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