Asked by tina
95.0 g of0.0 degrees celsius ice is added to exactly 100 g of water at 60.0 degrees celsius. when the temperature of the mixture first reaches 0.0 celsius the mass of the ice present is?
Answers
Answered by
DrBob222
Temperature of water must decrease by 60C; how much energy is lost by the water in doing so?
mass H2O x specific heat H2O x 60 = approximately 25,000
How much can we get from 95g ice melting? That is
95 x 334 J/g =about 32,000
The differeence is 32,000-25,000 = about 7,000 and 7000/334 = 21. Approximately 21 g ice did not melt.
I estimated here and there; you need to go through and redo the problem more accurately.
mass H2O x specific heat H2O x 60 = approximately 25,000
How much can we get from 95g ice melting? That is
95 x 334 J/g =about 32,000
The differeence is 32,000-25,000 = about 7,000 and 7000/334 = 21. Approximately 21 g ice did not melt.
I estimated here and there; you need to go through and redo the problem more accurately.
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