Ask a New Question

Asked by Sierra

Find all solutions in the interval [0,360) sin(4t)=ã3/2
13 years ago

Answers

Answered by Steve
sin 4t = √3/2

you know sin 60° = √3/2, so 4t=60° or 120°

t=15° or t=30°

Now, to get all solutions in [0,360), add multiples of 2pi/4 = 90°:

t = 15° + 90n° = 15,105,195,285
t = 30° + 90n° = 30,120,210,300
13 years ago
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions

find all solutions in the interval [0,2 pi) sin(x+(3.14/3) + sin(x- 3.14/3) =1 sin^4 x c... Find all solutions on the interval [0,2pi] for the following: 2sin^2(x)-5sin(x)=-3 cos^2(x)+... Find all solutions on the interval (0,2pi): 2-2cos^2=sinx+1 Find all solutions in the interval [0, pi], 2sec^2x+tan^2x-3=0 Find all solutions in the interval[0,2pi),cos x/2-sinx=0 Find all solutions on the interval [0.2pi) A) -3sin(t)=15cos(t)sin(t) I have no clue... b) 8... Find all solutions in the interval [0,2π) for cos(x - π/6) = 1 + cos(x + π/6). Show work, please an... Find all solutions in the interval [0,2π) sin3x−sinx=0 Find all solutions.In the interval (0, 2pi} of cos(2x) - 2 cos(x) = 1 Find all solutions in the interval [0,2π) that satisfy tan(x)sin²(x) = tan(x) .
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use