Asked by miranda
find all solutions in the interval [0,360degrees) sin(5x)=0
Answers
Answered by
Damon
sin 5 x = 0
well, zero and every time 5 x is a multiple of 180
if x = 0 , sin 5 x = 0
if x = 180/5 = 36, sin 5 x = 0
if x = 360/5 = 72
in fact for any multiple of 36 until we reach 9
9 * 36 = 324 and sure enough sin 5*324 = sin 1620 = 0
well, zero and every time 5 x is a multiple of 180
if x = 0 , sin 5 x = 0
if x = 180/5 = 36, sin 5 x = 0
if x = 360/5 = 72
in fact for any multiple of 36 until we reach 9
9 * 36 = 324 and sure enough sin 5*324 = sin 1620 = 0
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