Question

please help please show work so i can do others ok so i have to find the equation of the linethat contains given point and is parallel to the given line then write a slope intercept form if possible

(8,-4) y=-1/2x+11


I also have to do the same for this type and im stuck too

(-5,-6) x axis

Answer 1

write given line as y = m x + b
y = (-1/2) x + 11
so m = slope = -1/2)
we need the same slope so our line is of form
y = (-1/2) x + b, but we need to find b
use given point to find b
-4 = (-1/2)8 + b
-4 = -4 + b
b = 0
so
y = (-1/2)x + 0 or -2 y = x

Answer 2

slope of x axis is 0 so
y = 0 x + b
-6 = 0 (-5) + b
b = -6
so
y = -6
horizontal line six units below x axis