Question
Calculate the boiling point
a. 10.5 g FeCl3 in 2.11 102 g water
b.4.6% KCl by mass (in water)
c.0.140 m MgF2
a. 10.5 g FeCl3 in 2.11 102 g water
b.4.6% KCl by mass (in water)
c.0.140 m MgF2
Answers
DrBob222
The first one is done this way.
mols FeCl3 = 10.5/molar mass
molality = mols/kg solvent
delta T = i*Kb*m
Add delta T to 100 for new boiling point.
i = 4 for FeCl3, 2 for KCl and 3 for MgF2.
mols FeCl3 = 10.5/molar mass
molality = mols/kg solvent
delta T = i*Kb*m
Add delta T to 100 for new boiling point.
i = 4 for FeCl3, 2 for KCl and 3 for MgF2.