Asked by Sheena

Calculate boiling point and freezing point of this solution which contains 5.85g of C6H12O6 in 255g H2O. pleasee
Answered by Sheena
i've read formulas to use ro solve this problem but i don't know what delta T means. please tell me what formula to use and what delta T means thaaaank youu
Answered by S
As far as I know, Delta T means the difference in temperature. T final- T initial.
Answered by Don
First find molar mass of C6H12O6:
I found it to be 180.1566 g/mol

now find the ratio of moles
5.85/180.1566 = .0325mol

Molality of C6H12O6:
(.0325*1000)/255 = .127

note: the value 1000 is from the density of water which is 1.00g/mL

So freezing point:
delta_T = -k_f * m
k_f = 1.86 for water

so delta_T = -1.86*.127 + 0 = -.236 Celcius

For boiling:
delta_T = k_b*m
where k_b =.512

so

.512*.127 + 100 = 100.065 Celcius


Some check my work
Answered by Sheena
THANK YOU SO MUCH!
Answered by Sheena
please explain more about how to find the molality??
Answered by Sheena
oh i got it thank you!
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