Asked by russel

a tire inflated to a gauge pressure of 2 bars has a nail 3mm in diameter embedded in it. what is the force tending to push the nail out of the tire?

Answers

Answered by ajayb
F=Pressure*area
= 2*10^5(N/m^2)*pi*1.5*10^-6(m^2)
= 3*pi*10^-1 N
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