Asked by russel
a tire inflated to a gauge pressure of 2 bars has a nail 3mm in diameter embedded in it. what is the force tending to push the nail out of the tire?
Answers
Answered by
Steve
1 bar is 10^6 dynes/cm^2
The nail has a cross-section of pi*(3mm)^2 = pi*(.3cm)^2 = .2827cm^2
so, the force exerted is 2*10^6*.2827 = 5.65*10^5 dynes = 5.65N
The nail has a cross-section of pi*(3mm)^2 = pi*(.3cm)^2 = .2827cm^2
so, the force exerted is 2*10^6*.2827 = 5.65*10^5 dynes = 5.65N