Asked by Megan
A 20 N force acts on a 10 kg object parallel to the object's displacement. If the force acts for 32 m, what is the final kinetic energy, in J, of the object assuming it starts from rest?
Answers
Answered by
Elena
a=F/m = 20/10=2 m/s².
s=(v²-vₒ²)/2a.
vₒ=0
v²= 2as.
KE=mv²/2= m2as/2=mas=10•2•32=640 J
s=(v²-vₒ²)/2a.
vₒ=0
v²= 2as.
KE=mv²/2= m2as/2=mas=10•2•32=640 J
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