Asked by Anonymous

3 FORCES ACT ON MOVING OBJECT.FIRST FORCE HAS MAGNITUDE OF 80.0N AND DIRECTED DUE NORTH.ANOTHER HAS MAGNITUDE 60.0N AND DIRECTED DUE WEST.WHAT IS THE MAGNITUDE AND DIRECTION OF THIRD FORCE,SUCH THAT THE OBJECT MOVE IN CONSTANT VELOCITY?
Answered by Henry
F2+F1 = -60 + i80.
F2 + F1 + F3 = 0
-60 + i80 + F3 = 0
F3 = 60 - i80
tanAr = -80/60 = -1.333333
Ar = -53.13 = Reference angle.
A = -53.13 + 360 = 306.87 Deg.
F3 = 60 - i80 = 60 / cos306.87 = 100N. @ 306.87 Deg.

There are no AI answers yet. The ability to request AI answers is coming soon!