Asked by jon
Five forces act on an object: (1) 60.0 N at 90°, (2) 40 N at 0°, (3) 80 N at 270°, (4) 40 N at 180°, (5) 50 N at 60°. What are the magnitude and direction of a sixth force that would produce equilibrium
Answers
Answered by
bobpursley
convert these to N,E format and add. Then the equilibriat is the - of that.
F=60E+40N+80(-E)+40S+50sin60N+50cos60E
= E(60-80+50cos60)+N(40-40+50sin60)
figure those, and the negative is the equilbrant. I measured angles from N.
F=60E+40N+80(-E)+40S+50sin60N+50cos60E
= E(60-80+50cos60)+N(40-40+50sin60)
figure those, and the negative is the equilbrant. I measured angles from N.
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