Asked by MAdason

Five forces act on an object: 1: 60 N at 90 degrees, 2: 40 N at 0 degrees, 3: 80 N at 270 degrees, 4: 40 N at 180 degrees, and 5: 50 N at 60 degrees. What is the magnitude and direction of the 6th froce that would produce equilibrium?
Answered by drwls
The vector sum of the six forces must be zero. Write that in the form of two equations (one each for the x and y components). Then solve for the unknown components of the sixth force.
Answered by Teklu
At a point forces of 60N and 90N are acting and the angle between them is 60 degree. Determine the magnitude and the direction of their Resultant by graphical method

Answered by Anonymous
-30 N
Answered by Henry
Fr = 60[90o] + 40[0o] + 80[270o] + 40[180] + 50[60o].

X=60*Cos90+40*Cos0+80*Cos270+40*Cos180+50*Cos60 = 0 + 40 + 0 - 40 + 25 = 25 N.
Y=60*sin90+40*sin0+80*sin270+50*sin60 =
60 + 0 - 80 + 0 + 43.3 = 23.3 N.
Fr = X+Yi = 25 + 23.3i.

Fe = -25 - 23.3i = 34.2N[43.2o+180] =
34.2N[223.2o].


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