Question
Five forces act on an object: 1: 60 N at 90 degrees, 2: 40 N at 0 degrees, 3: 80 N at 270 degrees, 4: 40 N at 180 degrees, and 5: 50 N at 60 degrees. What is the magnitude and direction of the 6th froce that would produce equilibrium?
Answers
drwls
The vector sum of the six forces must be zero. Write that in the form of two equations (one each for the x and y components). Then solve for the unknown components of the sixth force.
Teklu
At a point forces of 60N and 90N are acting and the angle between them is 60 degree. Determine the magnitude and the direction of their Resultant by graphical method
Anonymous
-30 N
Henry
Fr = 60[90o] + 40[0o] + 80[270o] + 40[180] + 50[60o].
X=60*Cos90+40*Cos0+80*Cos270+40*Cos180+50*Cos60 = 0 + 40 + 0 - 40 + 25 = 25 N.
Y=60*sin90+40*sin0+80*sin270+50*sin60 =
60 + 0 - 80 + 0 + 43.3 = 23.3 N.
Fr = X+Yi = 25 + 23.3i.
Fe = -25 - 23.3i = 34.2N[43.2o+180] =
34.2N[223.2o].
X=60*Cos90+40*Cos0+80*Cos270+40*Cos180+50*Cos60 = 0 + 40 + 0 - 40 + 25 = 25 N.
Y=60*sin90+40*sin0+80*sin270+50*sin60 =
60 + 0 - 80 + 0 + 43.3 = 23.3 N.
Fr = X+Yi = 25 + 23.3i.
Fe = -25 - 23.3i = 34.2N[43.2o+180] =
34.2N[223.2o].