Asked by Greg B.
If Y varies inversely as X^2, determine what Y would be if X=2 and another point on the equation is (1,8)
How would I go about working this problem out?
How would I go about working this problem out?
Answers
Answered by
Reiny
Y varies inversely as X^2
can be written as
y = k (1/x^2) , where k is a constant.
using the given data, we can find k
given: when x=1, then y =8
sub that into the above equation
1 = k(1/1)
k = 1
so our equation is y = 1/x^2
and now given that x=2,
y = 1/2^2 = 1/4
can be written as
y = k (1/x^2) , where k is a constant.
using the given data, we can find k
given: when x=1, then y =8
sub that into the above equation
1 = k(1/1)
k = 1
so our equation is y = 1/x^2
and now given that x=2,
y = 1/2^2 = 1/4
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