Question
If x varies inversely as y2 (y square) and x = 4 awhen y = 9, what is the value of y when x = 9?
Answers
Steve
x = k/y^2
4 = k/81
now you have k, so plug in your new x value to find y.
4 = k/81
now you have k, so plug in your new x value to find y.