Asked by tuni

A massless rod of length 1.00 m has a 2.00-kg mass attached to one end and a 3.00-kg mass attached to the other. The system rotates about a fixed axis perpendicular to the rod that passes through the rod 30.0 cm from the end with the 3.00-kg mass attached. The kinetic energy of the system is 100 J.
(a) What is the moment of inertia of this system about this axis?
(b) What is the angular speed of this system?
Answered by bobpursley
moment inertia= sume of momentus= 1/2 3*.3^2+1/2*.1*.7^2

KE= 1/2 I w^2
solve for W
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