Question
A string going over a massless frictionless pulley connects two blocks of masses 5.9 kg and 9.5 kg. the 5.9 kg block lies on a 31 ◦ incline; the coefficient of kinetic friction between the block and the incline is µ = 0.22. The 9.5 kg block is hanging in the air. The 9.5 kg block accelerates downward while the 5.9 kg block goes up the incline with the same acceleration.Given g = 9.8 m/s^2 what is the acceleration
of the system?
of the system?
Answers
Fn = m1gcos31
Ff = mu Fn
Fnet = m2g - Ff - m1gsin31
Fnet = ma where m is total mass of system
Ff = mu Fn
Fnet = m2g - Ff - m1gsin31
Fnet = ma where m is total mass of system
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