Question
During a training exercise a cannon ball is fired with a muzzle velocity of
84.9 m/s at an angle of 45o above the horizontal. Determine how far from the cannon the ball will land when it hits the ground.
84.9 m/s at an angle of 45o above the horizontal. Determine how far from the cannon the ball will land when it hits the ground.
Answers
R = Vo^2*sin(2A) / g.
R = (84.9)^2*sin90 / 9.8 = 736 m.
R = (84.9)^2*sin90 / 9.8 = 736 m.
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