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A jogger runs 145m. in a direction 20.0 degrees east of north (displacement of vector A) and then 105m. in a direction 35.0 degrees south of east (displacement of vector B). Using components, determine the magnitude and direction of the resultant vector C for these two displacements.
Answers
Answered by
MathMate
Hints:
X-component of resultant
= ∑Di*cos(θi)
and
Y-component of resultant
= ∑Di*sin(θi)
D(1)=145m, θ(1)=90-20=70° (from x-axis)
D(2)=105m, θ(2)=-35° (from x-axis)
X-component of resultant
= ∑Di*cos(θi)
and
Y-component of resultant
= ∑Di*sin(θi)
D(1)=145m, θ(1)=90-20=70° (from x-axis)
D(2)=105m, θ(2)=-35° (from x-axis)
Answered by
:)
Thank you. I got now the answer. :)
Answered by
Anonymous
Why making fool give full answer
Answered by
Roger
thanks for the hint. why not the full answer
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