Ask a New Question

Question

A jogger runs at an average speed of 5.9 mi/h. If she starts a run at 11:15 am, what time is it after she covers 4.75 x 104ft?
15 years ago

Answers

DrBob222
I would convert 5.9 miles/hour to feet/hour (there are 5,280 feet in a mile) , then use
distance = rate x time
solve for time in hours and add to 11:15 A. M.
15 years ago
tiffany
11:54Am
12 years ago

Related Questions

A jogger runs 59 m due west, then changes direction and runs 83 m due north. What is the distance th... A jogger runs in a straight line with an average velocity of v1=6.6 m/s for t1=6.0 min, and then wit... A jogger runs in a straight line with an average velocity of 7.6 m/s for 6.3 min, and then with an a... IP A jogger runs with a speed of 3.10{\rm m/s} in a direction 25.0{^\circ} above the x axis. Find... A jogger runs eastward in a straight line with an average speed of 2.25 m/s for 4.98 min and then co... A jogger runs down the street at a rate of 1.1 m/s. She sees the finish line, and speeds up to a vel... A jogger runs around a circular track of radius 65 ft. Let (x,y) be her coordinates, where the orig... A jogger runs a distance of six miles at an average speed of four miles an hour, how many minutes di... a jogger runs a 9 m/s and is trailed by a bumblebee moving at 5 m/s and buzzing at a frequency of 27... A jogger runs eastward in a straight line with an average speed of 2 m/s for 5 minutes and then co...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use