Asked by Sara

A jogger runs down the street at a rate of 1.1 m/s. She sees the finish line, and speeds up to a velocity of 3.6 m/s over 1.1 s. What is the acceleration of the jogger?

Answers

Answered by bobpursley
acceleration=changevelociy/time=(3.6-1.1)/1.1 m/s^2
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